Find the derivative of 3/log8(x)
\[\large \frac{d}{dx}\frac{3}{\log_8x}\] So we'll want to start by using our change of base formula. \[\large \log_a(b)=\frac{\log_c(b)}{\log_c(a)}\]Where \(\large c\) is any new base value that we want it to be. In this problem we're going to let \(\large c=e\). This corresponds to the natural log, and is easy to take a derivative of.\[\large \log_a(b)=\frac{\ln b}{\ln a}\]
Applying this to the problem gives, \[\large \frac{d}{dx}\frac{3}{\log_8x} \qquad = \qquad \frac{d}{dx}\frac{3}{\left(\dfrac{\ln x}{\ln 8}\right)}\] Understand how I applied that rule? No derivative has been taken yet. Just steps that will make the process easier.
Ohh okay that's why I wasn't getting it. Thanks for the start(:
Cool c: Lemme know if you're still stuck.
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