Question

find the second derivative of the function: y=(2-2x^2+x^6)/x^9

Answer 1

\[y'=\frac{(-4^x+6x^5)}{x^9}-\frac{(9*(2-2x^2+x^6))}{x^{10}}\]

Answer 2

Is that the first or second derivative? (d^2y)/(dx^2)?

Answer 3

\[y''=\frac{(-4+30x^4)}{x^9}-\frac{(18(-4x+6x^5))}{x^{10}}+\frac{90(2-2x^2+x^6)}{x^{11}}\]

Answer 4

there is another way to solve this is by dividing all the terms by x^9

Answer 5

do you how to find the derivative of this form- numerator/denominator ,where both numerator and denominator are functions of some variable??

Answer 6

Can you please explain, Siddharth18?

Answer 7

y=(2-2x^2+x^6)/x^9 we can rewrite this now
\[y = 2x^{-9}-2x^{-7}+x^{-3}\]

Answer 8

if u differentiate this function it would be much easier than using the quotient rule, that i just used earlier...

Answer 9

well there is a standard rule to solve such a form.