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Mathematics 16 Online
OpenStudy (anonymous):

Help Please!! Suppose that R (x) is a polynomial of degree 7 whose coefficients are real numbers. Also suppose that R(x) has the following zeros: -2 + I, 2i Answer the following: A. Find another zero of R(x) B. What is the maximum number of real zeros that R(x) can have? C. What is the maximum number of non-real zeros that R(x) can have?

OpenStudy (amistre64):

complex zeros come in conjugate pairs

OpenStudy (anonymous):

So for imaginary numbers it's the same? so I would take -2+i, and 2i there would be 2 more zeros> -2-i and -2i? answer for A. really confused with the imaginary numbers in the equation.

OpenStudy (amistre64):

if (a+bi) is a complex zero of a polynomial, then so is (a-bi). they give you 2 different complex zeros, which means that we have 4 that we can account for. a 7 degree poly has at most 7 zeros total.

OpenStudy (amistre64):

yes,

OpenStudy (anonymous):

According to Fundamental Theorem of Algebra, two another zeros are the conjugate of -2+i and 2i, which is -2-i and -2i.

OpenStudy (anonymous):

My answer for 'A' would be. -2-i, and -2i correct?

OpenStudy (amistre64):

we can make a table of zeros :) z1 z2 z3 z4 z5 z6 z7 -2i 2i -2+1 -2-1 we can fill in the rest of the table with either 3 real zeros and 0 complex zeros z1 z2 z3 z4 z5 z6 z7 -2i 2i -2+1 -2-1 a b c OR we can fill it in with 1 real zero and 2 complex zeros (since they come in pairs) z1 z2 z3 z4 z5 z6 z7 -2i 2i -2+1 -2-1 a+bi a-bi c

OpenStudy (anonymous):

For question 'B'. The maximum number of "real" zeros would be the maximum numbers of degrees stated which is "7". So there are "7" real zeros correct?

OpenStudy (amistre64):

there cant be 7 real zeros if we already know that 4 are complex (imaginary)

OpenStudy (anonymous):

aaahhh so for question A- the total number of real zeros are the total sum of the complex (imaginary). -2+i, 2i, -2-i, and -2i...

OpenStudy (anonymous):

Sorry amistre this is just hard to wrap my head around.

OpenStudy (amistre64):

for "A" that would be the set of the total number of KNOWN complex zeros, yes

OpenStudy (anonymous):

so another zero would be what is NOT stated which is -2-i, and -2i.

OpenStudy (amistre64):

if we only focus on A at the moment, then that is correct. Another zero that we can be sure of is either: -2-i OR -2i both are acceptable results

OpenStudy (anonymous):

Awesome!!

OpenStudy (anonymous):

and for B. to find the maximum number of Real Zeros I would take the degrees given "7" and subtract the "known" zeros "4" to give me 3 real zeros.

OpenStudy (amistre64):

correct, there are only 3 zeros left, and they can all be filled with real numbers.

OpenStudy (anonymous):

You are a math genius- Finally I'm starting to get it.

OpenStudy (amistre64):

thnx :)

OpenStudy (anonymous):

For the Non- Real zeros... The only possibilities I have are complex... So I have "4" complex numbers and 3 real numbers. My answer would be 6 non-real zeros?!?!

OpenStudy (anonymous):

For the Non- Real zeros... The only possibilities I have are complex... So I have "4" complex numbers and 3 real numbers. My answer would be 6 non-real zeros?!?!

OpenStudy (amistre64):

yes, why? we know 4 complex already. and since complex zeros come in pairs, we can only fit 2 more UNKNOWN complex zeros inthe remaing spaces. 4+2 = 6 complex zeros max

OpenStudy (anonymous):

so the total number of complex numbers are all non-real zeros? Totaling 6

OpenStudy (amistre64):

correct

OpenStudy (anonymous):

WOW!!! I've been working on this for days- you are Great!! Just to sum it up A. -2-i, or -2i B. 3 real zeros C. 6 non real zeros

OpenStudy (amistre64):

that looks good to me :)

OpenStudy (anonymous):

tytytytyty!! I'm your fan :)

OpenStudy (amistre64):

good luck ;)

OpenStudy (anonymous):

Not sure how I do the medal thing on here...

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