Question

Integrate 1/(1+sqrt(x))

Answer 1

\[\Huge \int\limits \frac{1}{1+\sqrt{x}}dx\]

Answer 2

not so easy this one

Answer 3

what is this.... calculus???

Answer 4

yes

Answer 5

@Hero @experimentX

Answer 6

ohhh -.- imin algebra 1 can u help me?

Answer 7

i would do this
\(\Huge \int\limits \frac{1}{1+\sqrt{x}}dx=\Huge \int\limits \dfrac{\sqrt x}{\sqrt x} \frac{1}{1+\sqrt{x}}dx \\ \Huge= \int\limits \frac{\sqrt x+1-1}{\sqrt x(1+\sqrt{x})}dx\)

Answer 8

okay, i'm following

Answer 9

\( \Huge= \int\limits \frac{\sqrt x+1-1}{\sqrt x(1+\sqrt{x})}dx \\ \huge =\int \dfrac{dx}{\sqrt x}-\int \dfrac{dx}{\sqrt x(1+\sqrt x)} \)
now you can put u= \(\sqrt x+1\) in 2nd integral

Answer 10

did u get that ?

Answer 11

yes

Answer 12

could you now integrate both the integrals ?

Answer 13

looks like you can use trigs also