Need some help!
Graph 4x2 + y2 = 9. What are its lines of symmetry?
@hartnn @phi @ZeHanz @zepdrix
I would divide both sides by 9 \[ \frac{4 x^2}{3^2} + \frac{y^2}{3^2} = 1\] or, changing multiplying by 4 to dividing by 1/4 \[ \frac{x^2}{\frac{3^2}{2^2}} + \frac{y^2}{3^2} = 1\] or \[ \frac{x^2}{\left(\frac{3}{2}\right)^2} + \frac{y^2}{3^2} = 1\]
oh ok... but how does the graph look?
that form should ring bells See http://www.mathwarehouse.com/ellipse/equation-of-ellipse.php
would it be every line through orgin is line of symmetry or It has two lines of symmetry: the x axis and the y- axis @phi
does anyone else know
this is an ellipse |dw:1362588182543:dw|
I know what graph looks like but which is it
it looks symmetric about the x and y axes (i.e. left side = mirror image of right side. same for top and bottom)
oh ok so B.?
if B means x and y axes
this is B. ----> It has two lines of symmetry: the x axis and the y- axis
yes, that looks good
thank!
could you help on one more
What are the focus and the directrix of the graph of x = 1/24y^2?
anyone?
write it as y^2 = 24x and match this to the form y^2 = 4px so you have y^2 = 4* 6*x p is 6
does that mean the diretix is 6
or part of the focus??
the 6 means the focus is 6 in from the vertex and the directrix is 6 in the opposite direction
so focus would be (6,0)
directix = x=-6??
yes, that sounds right.
ok!
why wouldn't it be (0,6)
You have to know which way the parabola is opening up.
so u are sure its (6,0)
one way to figure it out is write y^2 = 4* 6*x as y = ± sqrt(24 x) x has to be positive (or you get imaginary values) y will be + and - the same value so it should look like this |dw:1362589310720:dw| the focus will have y=0 and some x value
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