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Mathematics 21 Online
OpenStudy (anonymous):

Need some help!

OpenStudy (anonymous):

Graph 4x2 + y2 = 9. What are its lines of symmetry?

OpenStudy (anonymous):

@hartnn @phi @ZeHanz @zepdrix

OpenStudy (phi):

I would divide both sides by 9 \[ \frac{4 x^2}{3^2} + \frac{y^2}{3^2} = 1\] or, changing multiplying by 4 to dividing by 1/4 \[ \frac{x^2}{\frac{3^2}{2^2}} + \frac{y^2}{3^2} = 1\] or \[ \frac{x^2}{\left(\frac{3}{2}\right)^2} + \frac{y^2}{3^2} = 1\]

OpenStudy (anonymous):

oh ok... but how does the graph look?

OpenStudy (phi):

that form should ring bells See http://www.mathwarehouse.com/ellipse/equation-of-ellipse.php

OpenStudy (anonymous):

would it be every line through orgin is line of symmetry or It has two lines of symmetry: the x axis and the y- axis @phi

OpenStudy (anonymous):

does anyone else know

OpenStudy (phi):

this is an ellipse |dw:1362588182543:dw|

OpenStudy (anonymous):

I know what graph looks like but which is it

OpenStudy (phi):

it looks symmetric about the x and y axes (i.e. left side = mirror image of right side. same for top and bottom)

OpenStudy (anonymous):

oh ok so B.?

OpenStudy (phi):

if B means x and y axes

OpenStudy (anonymous):

this is B. ----> It has two lines of symmetry: the x axis and the y- axis

OpenStudy (phi):

yes, that looks good

OpenStudy (anonymous):

thank!

OpenStudy (anonymous):

could you help on one more

OpenStudy (anonymous):

What are the focus and the directrix of the graph of x = 1/24y^2?

OpenStudy (anonymous):

anyone?

OpenStudy (phi):

write it as y^2 = 24x and match this to the form y^2 = 4px so you have y^2 = 4* 6*x p is 6

OpenStudy (anonymous):

does that mean the diretix is 6

OpenStudy (anonymous):

or part of the focus??

OpenStudy (phi):

the 6 means the focus is 6 in from the vertex and the directrix is 6 in the opposite direction

OpenStudy (anonymous):

so focus would be (6,0)

OpenStudy (anonymous):

directix = x=-6??

OpenStudy (phi):

yes, that sounds right.

OpenStudy (anonymous):

ok!

OpenStudy (anonymous):

why wouldn't it be (0,6)

OpenStudy (phi):

You have to know which way the parabola is opening up.

OpenStudy (anonymous):

so u are sure its (6,0)

OpenStudy (phi):

one way to figure it out is write y^2 = 4* 6*x as y = ± sqrt(24 x) x has to be positive (or you get imaginary values) y will be + and - the same value so it should look like this |dw:1362589310720:dw| the focus will have y=0 and some x value

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