how do I find the antiderivative of 2/x?
\[2 \int\limits \frac{dx}{x} = 2\ln(x) +c\]
where do you get c?
because this is an indefinite integral, u must add a constant at the end of every indefinite integral
the see come if u want to understand the proof in depth from Taylor series, and from integral definition, combined with differentiation definition
this is where the c comes from as i mentioned above, also some numerical integral methods can show this fact as well, whichever way u prefer to visualize the concept.
You could expand it a little. Because 2/x also accepts negative numbers, and ln(x) does not: \[\int\limits \frac{2}{x}dx= 2 \int\limits \frac{1}{x}dx= 2 \ln|x|+C\]which allows negative numbers to join in!
hmm, I still don't get how to find C, but I have some terms to search for :)
yes negative numbers are undefined that's why we ignore the absolute structure because its an axiom to mathematician....
you have add c at every indefinite integral take that for granted
you have to*
We cannot ignore the negative numbers is we have to evaluate:\[\int\limits_{-2}^{-1} \frac{1}{x}dx\]
because if ln(x) +c and want to differentiate that would be different from differentiating ln(x) with no constant i hope this helps
we are talking about indefinite integral not definite integral
as i said the world of mathematician is different
hmm, as an example, how would you go about finding c when f(x) = 2 / x ?
mathematicians
u have to have some initial values provided in the question to find c, this is called in general IVP, Initial Value Problem
hmm, I see. allright, I've got reading to do. Thanks for your help :)
if u want i can prove to u how the c comes into the integral but i am worried that u get confused
I'm confused enough, thanks ;)
hehehehe good luck, it is good to be confused some times you know...
have u done differential equations yet?
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