Need help solving 0 = −x^2 + 2.5x + 1 I have this formula, but I have no idea how to plug it in or how to write it down or what to do with the 2.5 Any help would be MUCH appreciated. H(t) = -16^2 + vt + s
\[ 0 = −x^2 + 2.5x + 1\] \[10x^2-25x+10=0\] \[2x^2-5x+2=0\]now if you can factor, then factor, if not use the quadratic formula
this one actually factors as \((x-2)(2x-1)=0\) so the rest should be ok
I don't understand how you got 10x^2, 25, and 10. Did you multiply by 10?
@satellite multiplied every member of the first equation by 10 to clear the decimals.
i hate decimals
then divide by the common factor of 5
When you factor, aren't you supposed to find the product of the last term and the sum of the middle term? When I did that, it said that -2 *-1 = 2 but 2 + -1 = -3 I checked it on Wolfram and it said that (x−2)(2x−1) was right, but is there something I'm missing?
yes, the leading coefficient is 2, not 1, so that whole "sum product" business needs to be readjusted
I've been trying to write and rewrite the equation from factoring but even when I rearrange it, I can't get -5 from -1 and -2.
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