Question

Prove the boolean identity using algebraic manipulation:

WY + W'YZ' + WXZ + W'XY' = WY + W'XZ' + X'YZ' + XY'Z


please helppp! :((

Answer 1

i'll try. and need you join.is it ok?

Answer 2

my strategy is cancel out the same term by term both sides to get the answer.

Answer 3

that's ok.if you don't try,why i have to.bye

Answer 4

sorry. i was away. just saw your reply

Answer 5

ok. take out a paper and divide it into 2 columns, left side write out the left side of equation and right side is the right of equation, we try together. link them by = side on top

Answer 6

done

Answer 7

are you done? both have WY, take them out, right?

Answer 8

left side W'YZ' =W'YZ'(X+X')=W'YZ'X +W'YZ'X'

Answer 9

left side,too, WXZ =WXZ(Y+Y')=WXZY +WXZY' add with the first term

Answer 10

do the same with all terms in 2 sides. you can see they are the same. it means the original one is equal.that's what i studied

Answer 11

hope this helps

Answer 12

thanks a lot...

Answer 13

ok.you' re welcome