Solve the system of equations by the addition method. x+y=-12 x-y=-12
If x + y = 12, and x - y = -12, y needs to be zero, correct? That would mean x is -12... Am I missing something here? Is there more information to this question?
they both equal to -12.
That's the only information/instructions.
With that being said, x = -12, and y = 0, but that's way too easy. There must be something I'm missing.
its a multiple choice question.. o:
What are the options?
(0, 12) (12, 0) (0, -12) (-12, 0)
Could you like show the step by step process of the work? O:
(x + y) & (x - y) = -12 y, as aforementioned, has to be zero, for the outcome remains the same if both subtracted and added. (x + 0) & (x - 0) = -12 For addition: x + y = -12 -12 - y = x -12 - 0 = x -12 - 0 = -12 -12 = x For subtraction, flip the signs.
oh. I understand. Thank you ^^;;
No problem. Any other questions you need help with?
Most of the questions on this quiz I am taking on blackboard is all related with systematic equations. . .
I can help.
8x+4y=-8 -2x-4y=-28
Multiple choice answers: (4, -10) (8, -10) (-6, 10) infinite number of solutions
I just want to learn how to approach this type of problem.
4y is a shared sequence, so finding that in one equation can potentially solve both... I'm working on it.
ok o :
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