Please look at the question below:

Question

anonymous · Answer

Prove that for all sufficiently large n $$ \frac{ 2n \log2 }{\log(2n+1) } - 1 \ge \frac{ \log2 }{ 2 }\frac{ 2n }{ \log 2n } $$

anonymous · Answer

Hi there! Hi there! You're going to want to post this question in the math section of OpenStudy. That way, you can be helped by people tutoring in that subject (there's a whole lot, trust me). If you post in the incorrect area, your question could be regarded as spamming, or it just may not get answered (or at least, not very quickly). Here is the link! Good luck, and enjoy OS! http://openstudy.com/study#/groups/Mathematics

anonymous · Answer

this is math right well you should go in the math section and ask them they might be able to help you

anonymous · Answer

oops... didn't mean to put "Hi there!" twice :)

anonymous · Answer

lol i dont think they will mind.

anonymous · Answer

:)

anonymous · Answer

lol XD

anonymous · Answer

If she's there... she hasn't said anything yet..

anonymous · Answer

ya ravina is there but he or she isnt awnsering.

anonymous · Answer

*checks watch* Well, I better go, then. :) Thanks for helping, hanna! :)

anonymous · Answer

your welcome.

anonymous · Answer

@ravina  Please ask this in the Math section.

dan815 · Answer

shud i take it as log 10 since its just log

aravindg · Answer

@tafkas77  did you apply for being an ambassador ? I think you will be  a great amby !!

anonymous · Answer

@AravindG wow, you do? Thanks! :) I did apply, but I heard that Preetha wanted to wait a bit before releasing the next batch. Maybe I'll apply again next time! :)