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Mathematics 13 Online
OpenStudy (anonymous):

how do I find the inverse of f(x)=(x-2)^2+4?

OpenStudy (anonymous):

You know that f(x) is the same as y so you can rewrite the equation as\[y=(x-2)^2+4\] Now all you have to do is interchange the x and y and solve so simplify and solve this for y\[x=(y-2)^2+4\]

OpenStudy (anonymous):

ok I get that thank you

OpenStudy (anonymous):

so it would be square root ofx-4 +2 right?

hartnn (hartnn):

if you meant \(\sqrt{x-4}+2\) then its correct.

OpenStudy (anonymous):

so how come when I put them in the calculator to graph them they arent opposite of each other

hartnn (hartnn):

opposite ? in what sense ? also more accurate answer will be \(\pm \sqrt{x-4}+2\)

OpenStudy (anonymous):

they are supposed to be the same thing but going in different directions on the graph

hartnn (hartnn):

no, who told you that ?

hartnn (hartnn):

like ln x and e^x are inverse of each other but they don't go in opposite direction....

OpenStudy (anonymous):

|dw:1362657878171:dw| thats a sketch of the first equation isnt the second supposed to be the same thing but going down

hartnn (hartnn):

no! you can't just visualize an inverse function, you have to get it algebraically...

OpenStudy (anonymous):

well in my assignment I am supposed to graph it

hartnn (hartnn):

you are talking about mirror image with x axis as mirror, thats not what inverses are...

hartnn (hartnn):

so, just graph the functions individually.... anything asked to verify ?

OpenStudy (anonymous):

Hi, I'm Dr. Professor to find inverse you have to follow these steps: Lets first start with an example, We have , f(x) = 2x+3 |dw:1362657923585:dw| Right, May be this much is clear. Now the Inverse function goes in this way, |dw:1362658040262:dw| So , the inverse of: 2x+3 is: (y-3)/2

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