how do I find the inverse of f(x)=(x-2)^2+4?
You know that f(x) is the same as y so you can rewrite the equation as\[y=(x-2)^2+4\] Now all you have to do is interchange the x and y and solve so simplify and solve this for y\[x=(y-2)^2+4\]
ok I get that thank you
so it would be square root ofx-4 +2 right?
if you meant \(\sqrt{x-4}+2\) then its correct.
so how come when I put them in the calculator to graph them they arent opposite of each other
opposite ? in what sense ? also more accurate answer will be \(\pm \sqrt{x-4}+2\)
they are supposed to be the same thing but going in different directions on the graph
no, who told you that ?
like ln x and e^x are inverse of each other but they don't go in opposite direction....
|dw:1362657878171:dw| thats a sketch of the first equation isnt the second supposed to be the same thing but going down
no! you can't just visualize an inverse function, you have to get it algebraically...
well in my assignment I am supposed to graph it
you are talking about mirror image with x axis as mirror, thats not what inverses are...
so, just graph the functions individually.... anything asked to verify ?
Hi, I'm Dr. Professor to find inverse you have to follow these steps: Lets first start with an example, We have , f(x) = 2x+3 |dw:1362657923585:dw| Right, May be this much is clear. Now the Inverse function goes in this way, |dw:1362658040262:dw| So , the inverse of: 2x+3 is: (y-3)/2
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