Ned currently has an account balance of $3,634.51. He opened the account 13 years ago with a deposit of $2,564.65. If the interest compounds twice a year, what is the interest rate on the account?
no idea to do this some pneone please help immediately
this web page explains it nicely http://www.purplemath.com/modules/expofcns4.htm
man no one cant't help me
The formula for future value is: F = P(1 + r/n)^(nt) Where F = future value, P = present value (or principal), r = interest rate written as a decimal, n = number of times interest is compounded per year, t = time in years
Thanks
You know F = 3634.51, t = 13, n = 2, P = $2564.65. Substitute all those values in the formula, and solve for r.
what' the rate
Solve this equation for t: 3634.51 = 2564.65*(1 + t/2)^(2*13)
i got 1.47
is that right :)
BTW, I meant to write r where t is in the equation with numbers. The equation is still correct, but where I wrote t, replace it with r. Solve this equation for r. 3634.51 = 2564.65*(1 + r/2)^(2*13) r can't be 1.47. Since r is the interest rate as a decimal that would mean the interest rate was 147%. That's not right.
the answer is 1.4
percent
3634.51 = 2564.65*(1 + r/2)^(2*13) First, divide both sides by 2564.65 3634.51/2564.65 = (1 + r/2)^26 After doing the division on the left side, take the 26th root of both sides.
I don't have a calculator on me, so I can't check on the answer.
what did u get as yur final answer
?
I don't have a calculator on me, so I can't check on the answer.
I can tell you what to do step by step, and you use your calculator to get the answer.
3634.51/2564.65 = (1 + r/2)^26 First, divide 3634.51 by 2564.65
Ok, I found the Google calculator. I'm doing it now.
I get r = 0.027
ok i plugged it in and got 1.4%
I got r = 0.027, so the interest rate is 2.7%
ohh ok isee how u did it :0
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