Find the surface area of the cylinder. 2009.6 in.2 401.9 in.2 803.8 in.2 602.9 in.2 Find the volume of the cylinder. 1607.7 in.3 2,845.7 in.3 6,430.7 in.3 401.9 in.3
can you guys help me?
The cylinder wall area is: 2*pi*r*h The area of each endcap is: pi*r^2 The volume of the cylinder is: pi*r^2*h
whats h
h = height
is it 1607.68
Just plug in the numbers into qwe's area equation.
i did the equation is it the answer i posted
Sorry, I had to figure out what you did. Yes, you are correct. 1607.68 is the answer using 3.14 as pi.
yay ok thx
what about the area?
Okay, first find the cylinder wall area using 2*pi*8^2
ok lemme do tht
401.92
Correct!! Now find the area of one endcap using pi*8^2
ok ima do that now
200.96
Correct again!! :-) Okay, but now we're in a little dilemma here... You have 4 answers, 1 of wich is absurd, 1 of which is the area of the cylinder wall alone, 1 is the area of the wall and 1 endcap, and 1 is the area of the wall and 2 endcaps. I'm going to guess that the answer is the cylinder wall and 2 endcaps, if that's okay with you. So that being the case, I would take the area of the single endcap you just got and double it to give you the surface area of both endcaps. Then I would add that number to the area of the cylinder wall.
803.84
Correct again! You'll be teaching ME this stuff pretty soon now! :-)
haha lol ya
thx alot if you wouldnt mind would you check my answer to this other question?
Which other question?
Find the volume of the given cone. 320 in3 1,244 in3 415 in3 622 in3 Im pretty sure its d but im not very good at these
Heheh...would you believe I've never taken the volume of a cone before? I had to look up the formula! But yes, I got 414.69 using my calculator (which takes pi out to a zillion places)
so would it be c
Yes, I would choose C. :-)
ok thx
The volume formula for a cone is v = 1/3 pi r^2 h So I did pi * 6^2 * 11 and got 1244.0706908215581224312067797787 Then I divided that by 3 to get: 414.69023027385270747706892659289
wooo long number
Yeah...the wonder of calculators, eh? :-) Unfortunately it can cause minor problems when limiting numbers to 2 places because, as you can see, the final answers have small discrepencies. But as long as you can recognize what's going on, then it's usually safe to pick the closest answer as I/we did here. :-)
ya bai! thx for the help
No problem again! Be well! :-)
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