ok so i had this on my test earlier in school, and i left it blank because i don't know how to do this ?SAMPLE: Part 1: The solution is x > 5 and x<=9. Part 2: There would be an open circle on 5 and a closed circle on 9. Part 3: The shading is between the two numbers. Be sure that you have included all three parts when answering each question. d - 1 > -3 and d + 2 < 5 -3k + 7 > -5 and -7k + 5 < -2 -5 < 2y - 3 < 23 (Hint: refer to example 2 in the lesson.) x - 4 < 5 or x + 2 > 15 5x - 4 > 6 or -4x + 5 > 1
d - 1 > -3 d + 2 < 5 d > -3 + 1 d < 5 - 2 d > -2 d < 3 part 1: The solution is d > -2 and d < 3 part 2 : There would be an open circle on -2 and an open circle on 3 part 3 : The shading is between the two numbers. =========================================== -3k + 7 > -5 -7k + 5 < -2 -3k > -5 - 7 -7k < -2 -5 -3k > -12 -7k < -7 -3k/-3 < -12/-3 -7k/-7 > -7/-7 k < 4 k > 1 part 1 : the solution is k < 4 and K > 1 part 2 : open circle on four and open circle on 1 part 3 : shading in between the two numbers ============================================ -5 < 2y - 3 2y - 3 < 23 -5 + 3 < 2y 2y < 23 + 3 -2 < 2y 2y < 26 -1 < y y < 13 part 1 : the solution is y < 13 and -1 < y part 2 : open circle on both numbers part 3 : shading in between the two numbers ============================================ x - 4 < 5 x + 2 > 15 x < 5 + 4 x > 15 - 2 x < 9 x > 13 part 1 : the solution is x < 9 and x > 13 part 2 : open circle on both numbers part 3: open circle on 9 shading to the left, open circle on 13 shaded to the right. ============================================ 5x - 4 > 6 -4x + 5 > 1 5x > 6 + 4 -4x > 1 - 5 5x > 10 -4x > -4 x > 2 -4x/-4 < -4/-4 x < 1 part 1 : solution is x > 2 and x < 1 part 2 : open circle on both numbers part 3 : open circle on 1 shaded to the left, open circle on 2 shaded to the right
how do you know there wil be an open circle and where it will be shaded?
It is only shaded(closed) if it is like this <= or =>, but if it is like this < or >, then it will be open. In other words, if there is no equal sign attached to the inequality, then the circle is open.
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