Can i get help finding three consecutive even integers such that when the first integer is multiplied by the third integer, the result is 2 more than 5 times the second integer.

Question

raden · Answer

let that number are, x, x+1, x+2
according information above :
x(x+2) = 5(x+1) + 2
solve for x

anonymous · Answer

i see. but i got stuck when i multiplied x and x because it equals x^2

anonymous · Answer

i dont know what to do with it when i add like terms

raden · Answer

simplify this, first
x(x+2) = 5(x+1) + 2
x^2+2x = 5x+5+2
x^2+2x = 5x+7
x^2+2x-5x-7=0
x^2-3x-7=0

raden · Answer

but, look no x's are integer number there !!

anonymous · Answer

do i solve for x in a algebraic solution?

raden · Answer

yes, use the quadratic formula

raden · Answer

quadratic equation formula i meant

anonymous · Answer

isnt that -b/2(a)?

raden · Answer

that is the sum of roots formula

raden · Answer

oppps... that is the formula to get x-vertex :)
the sum of roots is -b/a, sorry

raden · Answer

hai, i come back :)

raden · Answer

well, i want to show u how to get x's
use quadratic equation formula :
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