How many grams of iron (3) carbonate contains 17g of carbonate ions?
I could answer this and help you, but your name is offensive to OS and its users.
i don't understand how the name is offensive?
ok so iron 3 carbonate is Fe2(CO3)3
right?
give me one second
alright
My Public Apology to OSU!
do you mind helping @Preetha
yes i do think you need molar mass i'm researching a bit on this just so you get a good answer
thank you
I think you are trying to calculate how many g of Fe2(CO3)3 would be needed to get 17 g of CO3. If so then here it is: For every one mole of the Iron carbonate, you have 3 moles of CO3. So for 17 g of CO3 you need: 17 g CO3 x 1 mole of CO3/molar mass of CO3 x 3 moles CO3/1 mole Fe2(CO3)3 x molar mass of Fe2(CO3)3 /1 mole of Fe2(CO3)3. Does that make sense?
ok so the molar mass would be...55.8(2) + 12(3) + 16(9)=291.6
that sounds correct @Preetha :)
17 x 6.02x10^23 =1.02x10^25
then...1.02x10^25/ 180=5.7x10^22, is this right so far?
I dont know why you are multiplying by avogadro's number OSU. In this step, 17 g CO3 x 1 mole of CO3/molar mass of CO3 you have to convert the g to moles by dividing by the molar mass of CO3
so u dont use 6.02x10^23
?
No. How do you convert 17g to moles of CO3?
Molar mass of CO3 is 60.00907 ± 0.00004 g/mol oops
sorry my things wrong
17/60=.28
yes use my second eqution mol X g/mol = grams grams / g/mol = moles.
do i multiply .28 by 3
grams/ g/mol= moles to convert
wait one sec
preetha am i wrong?
I'm sorry my helps not that good on this question I slightly forget learning this but i think you do multiply by three
ok so .28 x 3 = .84/291.6....
is this right?
so the answer is .003?
yes I would asume so! I'd check with some peers too are you in a home school?
nope
then please check with someone I really hope that you get this correct I'm sorry I couldn't help more
its fine thank you
do you have anything else? I can try to help you
nope, thank you
:) sorry bye bye
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