Question

my answer book looks like this:

(1−cot2(w)+cos2(w)cot2(w))/csc2(w)


down to:

(1−cot2(w)(1−cos2(w))/csc2(w)


but i'm not sure how

Answer 1

those were supposed to be squares

Answer 2

you break it as

Answer 3

\[\frac{ 1-\cot 2w }{ \csc 2w }+\frac{ \cos 2w \cot2w }{ \csc 2w }\]

Answer 4

sorry, new to this computerized math part, but they were supposed to be :

\[(1-\cot^2(w) + \cos^2(w) * \cot^2(w) ) / \csc^2(w) = \sin^4(w)\]

Answer 5

but what i cannot understand is how the book demonstrates the following

Answer 6

\[(1-\cot^2(w) * (1-\cos^2(w)) / \csc^2(w) = \sin^4(w)\]

Answer 7

i am not sure where the 1-cos^2(w) comes from

Answer 8

\[\frac{ 1-\cot^2(w) + \cos^2(w) * \cot^2(w) }{ \csc^2(w) } = \sin^4(w)\]

Answer 9

ok, i misunderstand your cot2 . i got it. i know where it comes from

Answer 10

sorry i am very new to this today

Answer 11

wait/ \[\frac{ (1-\cot^2w +\cos^2 w)\cot^2 w }{ \csc^2 w }\]. is it your problem?

Answer 12

Prove:

\[\frac{ 1-\cot^2(w)+\cos^2(w)*\cot^2(w) }{ \csc^2(w) } = \sin^4(w)\]

Answer 13

ok , i'll try

Answer 14

ok i rearrange the numerator , just count the numerator only,

Answer 15

ok i rearrange the numerator , just count the numerator only,\[\cos^2\cot^2 -\cot^2+1 = \cot^2(\cos^2-1)+1= -\cot^2(1-\cos^2)+1\]

Answer 16

=\[-\cot^2\sin^2 +1 = -\cos^2 +1 =\sin^2\]

Answer 17

now, add the denominator in, 1/csc^2 = sin^2. you get sin^4. is it right?

Answer 18

ok, not sure why that was causing me so much difficulty, thank you

Answer 19

LOl, to smart student, everything is challenged. you think too high. that's it