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Mathematics 9 Online
OpenStudy (anonymous):

The population for a city is 39,194 and grows continuously at a rate of 6.9% each year. What is the approximate population in 17 years?

OpenStudy (kropot72):

The equation needed to solve this continuous growth question is: \[P _{t}=P _{i}e ^{rt}\] where Pt is the population after t years of continuous growth, Pi is the initial population, e is the exponential number, r is the annual growth rate as a decimal and t is the number of years from the initial year.

OpenStudy (anonymous):

how do uset it up

OpenStudy (anonymous):

i mean how do u set it up

OpenStudy (kropot72):

\[P _{t}=39194\times e ^{(0.069\times 17)}=you\ can\ calculate\]

OpenStudy (anonymous):

whats e

OpenStudy (kropot72):

I told you at the beginning that e is the exponential number.

OpenStudy (anonymous):

what was yur final answer i got 4.6% ?

OpenStudy (kropot72):

the value of e is approximately 2.71828

OpenStudy (kropot72):

The final answer is a number much greater than 39,194. It is not a percentage.

OpenStudy (anonymous):

126,662

OpenStudy (kropot72):

That is the correct answer.

OpenStudy (anonymous):

thanks

OpenStudy (kropot72):

You're welcome :)

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