Question

solve for x 2x-3/3 +5-x/2 =3

Answer 1

\[\frac{2x-3}{3} + \frac{5 - x}{2} = 3\]

Answer 2

Is that it?

Answer 3

yes

Answer 4

\[\frac{2x - 3}{3} + \frac{5 - x}{2} = \frac{6}{2}\]\[\frac{2x - 3}{3} = \frac{6}{2} - \frac{5 - x}{2}\]\[\frac{2x - 3}{3} = \frac{6 - 5 + x}{2} \]\[\frac{2x - 3}{3} = \frac{1+ x}{2}\]\[2(2x-3) = 3(1+x)\]

can you finish the rest?

Answer 5

i dont understand

Answer 6

6/2 = 3, right?

Answer 7

yes

Answer 8

Okay, so I replaced 3 with 6/2. Now \(\frac{5 - x}{2}\) and \(\frac{6}{2}\) have the same denominator.

Answer 9

So I subtract \(\frac{5-x}{2}\) from both sides. Once I do that, I have to subtract:
\(\frac{6}{2} - \frac{5 -x}{2}\)

Answer 10

When I do that, I end up with \(\frac{1 + x}{2}\)

Answer 11

So now what's left is:

\(\frac{2x-3}{3} = \frac{1+x}{2}\)

Which you use cross multiply to get \(2(2x-3) = 3(1+x)\)

Answer 12

Can you finish solving from there?

Answer 13

not sure but I'll try

Answer 14

thanks

Answer 15

Did you solve for x? If so, what did you get?

Answer 16

is it 1

Answer 17

No