((-5+sqrt13)/2)y+(-5-sqrt13)/2=0 I need to solve for Y.
please anyone I dont know how to get started
do you know how to solve this
please
\[\frac{-5+\sqrt{13}}{2}y+\frac{-5-\sqrt{13}}{2}=0\]
Do I have it right?
yes
Subtract the second fraction from both sides.
Yes that is when I get the problem. That step and the one that follows
\[\frac{-5+\sqrt{13}}{2}y=- \frac{-5-\sqrt{13}}{2}=\frac{5+\sqrt{13}}{2}\]
Now multiply both sides of the equation by the reciprocal of the coefficient of y
Ok, when i do that for some reason everything cancels out
\[y=\frac{5+\sqrt{13}}{2} \times \frac{2}{-5+\sqrt{13}}=\frac{\sqrt{13}+5}{\sqrt{13}-5}\]
ok Im following
Now rationalize the denominator by multiplying numerator and denominator by sqrt13+5
ok
\[y=\frac{\sqrt{13}+5}{\sqrt{13}-5}\times\frac{\sqrt{13}+5}{\sqrt{13}+5}=\frac{13+10\sqrt{13}+25}{13-25}=\frac{38+10\sqrt{13}}{-12}\]
Now divide out the common factor 2 from numerator and denominator.
ok following along
Can you divide out the 2?
no :( Im sorry I have not done this in a long time.
What is 38 divided by 2?
19
ok. Replace the 38 with 19. What is 10sqrt13 divided by 2?
5sqrt13?
yes. Replace the 10sqrt13 with 5sqrt13. What is -12 divided by 2?
-6
Yes. replace the -12 with -6 and now you are done.
oh ok, for some reason the answer I have is (5sqrt 13 +13)/26 ?
It makes since when I followed along with you, but the answer does not make since?
Would you please check and make sure the problem is posted exactly as it is stated in your book?
yes, it could be wrong in the book
You have helped me alot thank you so much:)
yw
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