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Mathematics 15 Online
OpenStudy (anonymous):

find a basis for the null space of A (see attachment)

OpenStudy (anonymous):

\[\left[\begin{matrix}1 & -1 &3 \\ 5 & -4 & -4\\7 &-6 &2\end{matrix}\right]\]

OpenStudy (anonymous):

@camoJAX this time, it's me. help, please

OpenStudy (anonymous):

trying to see now

OpenStudy (anonymous):

taking longer than i thought, still going though

OpenStudy (anonymous):

First find it's row reduced echelon form.

OpenStudy (anonymous):

yep and you'll get \[1x _{1}-1x _{2}+3x _{3}=0\] \[1x _{2}-19x _{3}=0\] still working though

OpenStudy (anonymous):

yes, I got it as \[\left[\begin{matrix}1 & -1 &3 \\ 0 & 1 & -19\\0 & 0 & 0\end{matrix}\right]\]

OpenStudy (anonymous):

bottom row will be all zeros

OpenStudy (anonymous):

@camoJAX bingo.

OpenStudy (anonymous):

how to make matrices on here?

OpenStudy (anonymous):

stack -22,19, 1 on each other and thats the answer

OpenStudy (anonymous):

go to equation right below this box. you can see many symbol, choose matrix symbol, you will have something like ? ? .. whenever see? put the number there and & ? put number at ? if you need 3 terms add 1 & symbol and then type the number there. if you want to take 1 more row, \\ and repeat

OpenStudy (anonymous):

To make a matrix type: \begin{bmatrix} a & b & c \\ d & e & f \\ g & h & i \end{bmatrix} You use & to delimit columns and \\ to delimit rows.

OpenStudy (anonymous):

@camoJAX 16 not 22

OpenStudy (anonymous):

\[\left(\begin{matrix}16 \\ 19\\1\end{matrix}\right)\]

OpenStudy (anonymous):

my question starts from now on. I got it but is it the null space or we have to break it down to 3 vectors as

OpenStudy (anonymous):

You have one free variable, so your null space is just one column

OpenStudy (anonymous):

yep dont know why i was thinking negative plus a negative and made the 19 positive then subtracted it from -3. my bad

OpenStudy (anonymous):

\[\left(\begin{matrix}16 \\ 0\\0\end{matrix}\right)\left(\begin{matrix}0 \\ 19\\0\end{matrix}\right)\left(\begin{matrix}0 \\ 0\\0\end{matrix}\right)\]

OpenStudy (anonymous):

\[ x_1 = x_2 - 3x_3 = 19x_3-3x_3=16x_3 \\ x_2 = 19x_3 \]

OpenStudy (anonymous):

meant neg x neg lol

OpenStudy (anonymous):

thanks a lot both friends. so, since I have 1 free variable, 1 column basis in null space. if I have 2 , 2 columns basis. is it correct?

OpenStudy (anonymous):

Yes, one column per free variable.

OpenStudy (anonymous):

agree

OpenStudy (anonymous):

thank you very much. "The power of cooperation"

OpenStudy (anonymous):

@camoJAX which class do you have now?

OpenStudy (anonymous):

i'm still on Cal homework right now

OpenStudy (anonymous):

cal3? which school?

OpenStudy (anonymous):

yea Cal 3, Lamar Univ..kinda little,not too big school in TX

OpenStudy (anonymous):

still better than me, I am in community college.

OpenStudy (anonymous):

I am struggling with 3 math courses this semester. I have cal3, linear algebra and discrete

OpenStudy (anonymous):

that doesn't mean anything just depends what you do with your knowledge

OpenStudy (anonymous):

i'm taking those too except discrete

OpenStudy (anonymous):

my discrete is level 2, too many things to do. terrible

OpenStudy (anonymous):

i never heard of discrete but just looked it up and I pity you bro (...or sis) lol

OpenStudy (anonymous):

sister. no choice for me. my major is math. how can I avoid math courses?

OpenStudy (anonymous):

what is your major?

OpenStudy (anonymous):

true, sometimes math can be difficult but I love it when I'm able to solve a problem.

OpenStudy (anonymous):

Civil Engineering

OpenStudy (anonymous):

Lol. not lesser than me in math. for sure

OpenStudy (anonymous):

ok, being fan each other to get help whenever we need, deal?

OpenStudy (anonymous):

definite deal

OpenStudy (anonymous):

hey , my pro gives me a challenge question, deal after spring break, you can take a look and if you have time, think about helping me. i didn't have the solution yet. the problem is : why the procedure to get transition matrix from B to B' work. show your proof.

OpenStudy (anonymous):

it means P from B-->B' is |B'|B|----> | I | P from B -->B'|. why it works.

OpenStudy (anonymous):

the question is due after the break? your break is March11-15?

OpenStudy (anonymous):

no need to press yourself. It is just extra credit, i don't need it that much. my break from 3 to 10. I am during break time. if not, how can i have time to play here

OpenStudy (anonymous):

ohh you're on break now. I thought you probably just got on this site whenever. thats what i do

OpenStudy (anonymous):

i wanna know the answer now, i'll be thinking about it though

OpenStudy (anonymous):

too bad. I asked, pointed at particular people who has smartscore at top 99 -100 all of them say " sorry, I cannot help" or "sorry,it 's not my strong".

OpenStudy (anonymous):

i can ask my prof if I never figure it out

OpenStudy (anonymous):

ok. it's too late, I have to go to bed now. nice to meet you. whenever you got it, send me message.

OpenStudy (anonymous):

cool, night. nice to meet you also

OpenStudy (anonymous):

bye bye

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