Question

Find the maximum or minimum of the following quadratic function: y =x2 - 10x + 25.
A. 0
B. 25
C. -25
D. 50

Answer 1

max is the second coordinate of the vertex
first coordinate is \(-\frac{b}{2a}=-\frac{-10}{2}=5\)

Answer 2

second coordinate is what you get if you replace \(x\) by \(5\)

Answer 3

or you might recognize this as a perfect square, namely
\[y=(x-5)^2\] and since it is a square , the smallest it can be is zero

Answer 4

so our answer is 25 right?

Answer 5

@jim_thompson5910

Answer 6

no dear, the answer is the minimum is zero, not 25