Question

Can someone explain to me why sec10* / csc10* = 1? ==> sec10* = csc10*

Answer 1

\[\frac{a}{b}=1\iff a=b\]

Answer 2

sec(10*) = csc(10*) --> This is a false statement.

sec(10*) = csc(80*) --> They are cofunctions but not reciprocal functions

Answer 3

good point

Answer 4

But if sec10* / csc10* = 1 is True


Then why not sec10* = csc10*

Answer 5

Why do you think this is true: sec10* / csc10* = 1 ?

Answer 6

Are you telling me that it is not?

Answer 7

I am asking you why you think it is true.
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sec(10) / csc(10) = tan(10)

Answer 8

Alright then find the exact value of: - sec10* / csc 80*

Answer 9

secant and cosecant are cofunctions

Answer 10

What do you mean by that satellite? :)

Answer 11

lets look at a triangle

Answer 12

you can see from the triangle that \(\sec(10)=\frac{h}{b}\) and also that \(\csc(80)=\frac{h}{b}\) they are the same

Answer 13

that is because \(10+80=90\) or \(80=90-10\) which ever you prefer
so you can see from the picture that in general
\[\sec(\theta)=\csc(90-\theta)\]

Answer 14

same works for cosine and sine
and cotangent and tangent
that is why they are called "co - functions"

Answer 15

so since \(\sec(10)=\csc(80)\) you also have
\[\frac{\sec(10)}{\csc(80)}=1\]

Answer 16

in all fairness this is not what you wrote in the question
you had \(\frac{\sec(10)}{\csc(10)}=1\)which is false

Answer 17

I was marely trying yo understand the concept of it

Answer 18

to*

Answer 19

@satellite73 Can you please solve for me - sec10*/csc80* ?

Answer 20

-sec(10) divided by csc(80) = - 1