Question

s=t^6-5t^5

Answer 1

wat r u trying to find out?

Answer 2

find the value of t (other than 0) at which the accelerationn is equal to zero

Answer 3

You have to take second derivative of both sides.

Answer 4

I tried that I don't think I'm doing it correctly :s

Answer 5

Just take derivative two times.
\[\Large a(t) = \dfrac{d^2}{dt^2} t^6 - 5t^5= \dfrac{d}{dt}\dfrac{d}{dt} t^6 - 5t^5 = \dfrac{d}{dt} 6t^5 - 25t^4 = \boxed{30t^4 - 100t^3}\]