Question

Please help Verify the identity. cot^2x/csc x +1 = 1=sinx /sinx

Answer 1

\[ \frac{ \cot^2x}{ \csc x +1} = \frac{ 1-sinx }{sinx} \]

Answer 2

please HELP! :))))

Answer 3

(Cot^2x)/(Cscx-1) = (1 - Sinx)/(Sinx)

L.H.S. = (Cot^2x)/(Cscx-1) = (cosx/sinx)^2/(1/sinx - 1)

L.H.S. = cos^2x/sinx(1-sinx) = (1-sin^2x)/sinx(1-sinx)

L.H.S. = (1+sinx)(1-sinx)/ sinx(1-sinx)

L.H.S. = (1 - sinx) / sinx = R.H.S. Is this right???