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Logarithms: 2^(x+1)=3^x
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You should apply a logarithm. Since you have base 2 and 3, just pick a familiar base. \(log(2^{x+1}) = log(3^x)\) This leads to \((x+1)log(2) = xlog(3)\)
umm so what is x = ?
Solve for it.
This requires a little algebra. Don't let log(2) or log(3) scare you. Those are just numbers, like 7 or 4 or \(\sqrt{2}\) or \(\pi\).
i got log2/ (log3-log2) not sure if its correct?
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Well, there shoudl be an "x =" in there, somewhere. Good work.
thanks
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