Without using a calculator, evaluate (cos(30))^2−(sin(30))^2= 30's are degrees.
use the identity : cos^2 (x) - sin^2 (x) = cos(2x)
here,given x=30 deg
oh and the 2's are supposed to be like ^2. not just multiplying.
yup, that is a squared sign
yes i know... i was just letting you know. so what you said is still right, correct?
if u put x=30 to the identity above : cos^2 (x) - sin^2 (x) = cos(2x), giving us cos^2 (30) - sin^2 (30) = cos(2 * 30) = cos60, right ?
i dont get where you are getting cos(2x)...
that is one of identity in trigono, it must be in ur book, right
uhm, i am sure it is. but we didnt learn it that way. anyway, continue.
well, the alternative way did u memorize the value of sine, cos, tangen for the specials angles in trigo ?
cos30 and sin30 is very familiar, because it is the special angle
whatt's cos30 = ... sin30 = ...
i have the unit circle? if that is what you mean...
sqrt3/2 correct?
and 1/2
yup, for cos30
correct again :)
yayyyyy (:
so sqrt3/2-1/2...
now, the original ques is cos30 squared - sin30 squared = (sqrt(3)/2)^2 - (1/2)^2 = 3/4 - 1/4 = ... ?
1/2 :D
you are my new friend!!! thank you sooooo mush :DDD
that's right it's same like cos60, what i said before :)
you're welcome
wow thats an easier way of thinking about it!
actually, YES!! hhe
this woman has us going around the world when we can just walk across the street -_-
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