Question

I dont understand this question:
Rewrite each of the following in the form of a (x+p)^2+q where a, p and q belongs to real numbers:
1) 3x^2+6x-4
2)-2x^2-8x+4

Answer 1

this question is asking u to use complete square method

Answer 2

i dont know how to do that method

Answer 3

\[ax^2+bx+c=a(x-p)^2+q\]
where
\[p =-\frac{b}{2a} \space and \space q = c-\frac{b^2}{4ac}\]

Answer 4

so look at ur first equation 3x^2+6x-4, this means a=3, b=6 and c =-4

Answer 5

put those numbers in the above formulas u'll get the required answer

Answer 6

p=-6/(2.3)=-1, and q=-4-((36/4.3.(-4))

Answer 7

this is one way to do it, the other way to solve this problem is by doing the following

Answer 8

3x^2+6x-4=0, so divide both sides by the coefficient of x^2 which is 3

Answer 9

x^2+2x-4/3=0

Answer 10

so are the p and q values -1 and -112?

Answer 11

well if u did as i told u then yes

Answer 12

so if those are the values then i just rearrange the question into the form of a(x+p)^2+q?

Answer 13

exactly

Answer 14

so for the first question would it be, 3(x+-1)^2+-112?

Answer 15

you mean -112

Answer 16

yes no plus sign

Answer 17

3(x-1)^2-112?

Answer 18

yeah thats it right?

Answer 19

yes

Answer 20

so try doing question 2

Answer 21

i do exactly the same thing for question 2 correct?

Answer 22

yes

Answer 23

is the p value for question 2 = -2?

Answer 24

ok

Answer 25

and is the q value = 2?

Answer 26

because thats what i calculated