Question

find the values of s for which the quadratic equation x^2-2(s-3)x+(s^2-4s-5)=0 has real roots

Answer 1

for real roots, the discriminant \(b^2-4ac \ge 0\)
can you find a,b,c for this ?

Answer 2

how would you find the values of a, b and c?

Answer 3

compare \(x^2-2(s-3)x+(s^2-4s-5)=0 \)
with \(ax^2+bx+c=0\)

Answer 4

i dont understand, would the b value be 2(s-3)x?

Answer 5

'b' is the co-efficient of x
so, b = -2(s-3)

Answer 6

oh, so what about for a then? would be 1 because its x^2?

Answer 7

or would it be 0?

Answer 8

ax^2 ---->1x^2 --->a=1

Answer 9

oh yeah