Question

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Answer 1

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What is an equation of a parabola with the given vertex and focus?

vertex: (–2, 5); focus: (–2, 6)
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Answer 2

a general formula for the equation of a parabola

with the vertex is at the point \[(h,k)\] is
\[(x-h)^2=4p(y-k)\]
\(p\) is the focal length , ie distance between the vertex and focus

Answer 3

the distance/ length between two points
\((x_1,y_1), (x_2,y_2)\) on in the x-y plane is

\[ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]

Answer 4

can you find the focal length ?

Answer 5

vertex: (–2, 5); focus: (–2, 6)

Answer 6

\[(x_1,y_1)=(-2,5)\\(x_2,y_2)=(-2,6)\]

Answer 7

right the focal length is 1 unit ✓

Answer 8

now just substitute the vetex and the focal length into

\[ (x−h)^2=4p(y−k)\]

Answer 9

yes

Answer 10

you might want to simplify

Answer 11

wait you forgot the ^2

Answer 12

now simplify

Answer 13

well if it was me i would want the final result to be y= ...

Answer 14

no

Answer 15

i not sure what you are doing ,

Answer 16

(x+2)^2=(4)(y-5)

(x+2)(x+2)=4y-4×5

Answer 17

no

Answer 18

...

Answer 19

simplify until you get
y=

then stop

Answer 20

im going now

Answer 21

What do you want?

Answer 22

✓

Answer 23

yer