Question

Give the general solution for :
Tan (2x) + tan (x) = 1

Answer 1

This is the answers from WolframAlpha
C[1] Integers
x= -2.83998+6.28319 C[1]
x= -2.0026+6.28319 C[1]
x= -0.976957+6.28319 C[1]
x= 0.301616+6.28319 C[1]
x= 1.13899+6.28319 C[1
x= 2.16464+6.28319 C[1])

Answer 2

@siddarth95 Is it clear

Answer 3

medal If I'm right

Answer 4

I was hoping for the process to reduce it to the form of x=n(pi) + y (angle)

Answer 5

you dont get medal for coppying answers !! i think so!! :)

Answer 6

\[x=\tan^{-1} \frac{ 1 }{ 3 }\]

Answer 7

oh no no ignore it!!

Answer 8

i did 1 step wrong!!

Answer 9

@deena123 The function you applied is truly wrong, @siddarth95 do you expect a elaborated answer

Answer 10

\[\tan^3x-\tan^2x-3\tan x+1=0\]

Answer 11

If not elaborate atleast to the level of know what to simplify

Answer 12

Dude, question is a good one to try for IIT's here's the solution :

open tan2x as first answer and convert it into an equation of tanx

put tan x = y

then take y to R.H.S to make it 1-y

open the denominator of L.H.S. as 1-y^2 = (1+y) (1-y)

take 1-y to R.H.S to make it (1-y)^2

then 1-y = +L.H.S. or -L.H.S.

solve for both cases independently.

Source: http://in.answers.yahoo.com/question/index?qid=20110318113330AACstbi

Answer 13

@siddarth95 Its wat u wanted