Question

Requesting a double check of my answers and a step by step for question "b" please.

Answer the questions below about the quadratic function.
f(x)=-3x^2+6x-6
a. Does the function have a minimum or maximum value?
Answer: Maximum- the parabolas vertex is shifted downward

b. Where is the functions minimum or maximum value?
Answer: ?????

c. Where does the minimum or maximum value occur?
Answer: x= (1,-3)

Answer 1

a) answer : maximum, because the leading coefficient it negative, therefore the parabola opens down. not because of the vertex

Answer 2

b) the function has a maximum value at the second coordinate of the vertex
the first coordinate of the vertex is \(-\frac{b}{2a}=-\frac{6}{2\times (-3)}=1\) and the second coordinate of the vertex is \(-3\times 1^2+6\times 1-6=-3+6-6=-3\)

Answer 3

the short answer to b) is \(-3\) and the short answer to c) is \(1\)

Answer 4

For a. because (a<0) and the leading coefficient is a negative number- gotcha!

Answer 5

i am a little confused on the wording to b)
i take it to mean WHAT is the functions maximum value

Answer 6

"where" is a bit ambiguous

Answer 7

yes for "b" it is what is the functions maximum value.

Answer 8

ok, in that case the answer is "the maximum value is \(-3\)"

Answer 9

because the extreme value is -3 right?

Answer 10

for b. I'm still confused- it looks like 1 is on the x axis and -3 is on the y. I won't have to put both down for b? Just the y axis?

Answer 11

so it wouldn't be (1,-3) it would just be -3

Answer 12

Thanks again satellite!