Question

How far apart are the foci of an ellipse with a major axis of 26 feet and a minor axis of 24 feet?

Answer 1

a^2+b^2=c^2

Answer 2

do i just put the numbers into the equation? :/
these are the answer choices:4 feet
5 feet
10 feet
20 feet

Answer 3

If the major axis is 26, then 2a is 26 and a is 13. If the minor axis is 24, then 2b is 24 and b is 12. Use the values of a and b to calculate c

Answer 4

do you know the Pythagorean triples or no

Answer 5

hmm no i don't

Answer 6

what do you mean 2a? a? 2b?

Answer 7

The distance between the focal points is 2a=26 and 2b=24

Answer 8

so plug here a^2+b^2=c^2

Answer 9

The length of the major axis is 2a and that of the minor axis is 2b like @begzat said. Find the eccentricity of the ellipse sing \[e ^{2}= 1 - b ^{2}/a ^{2}\] [when a>b] .. the distance between the focii is 2ae

Answer 10

using*

Answer 11

thanks :)