Question

Differential equation question.

Answer 1

that's dy/dx that got cut off at the top.

Answer 2

My work is as follows:

dy/dx -2y/x = x^2
dy/dx + (-2/x)y = x^2

m = e^(integral -2/x) = 1/x^2

dy/dx *1/x^2 + (-2/x)y *1/x^2= x^2 *1/x^2

(This is where I think I'm going wrong)
integral dy/dx (1/x^2 * y) = integral 1
1/x^2 * y = x + C
y = x^3 + C

When y = 0 and x =1, C = -1

When x = 3, y = 26

Answer 3

@Nanoman u got wrong in the last step
y/x^2 = x + C
y = x^3 + C x^2

Answer 4

@Nanoman u got the correct value of C = -1
so ur final answer would become
y = x^3 - x^2
i hope u can find y(3) now?

Answer 5

ohhh..... thanks!

Answer 6

:-)