Mathematics
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OpenStudy (anonymous):
find the derivative of f(x) = (3x^2 - 3x + 1)/(2x). Directions, put 2x under each term and simplify. Then take the derivative.
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OpenStudy (anonymous):
@satellite73 can u help?
OpenStudy (anonymous):
@onegirl hints has been given in the ques
so what will u get after simplifying ?
OpenStudy (anonymous):
ok hold on
OpenStudy (anonymous):
after i put 2x over each term
f(x) = 3x^2/2x – 3x/2x + 1/2x
f(x) 3/2 x + 3/2 + 1/2x
f’(x) = 3/2 + 0 - 1/2x^2
f’(x) = 3x^2 – 1
OpenStudy (anonymous):
last step is wrong
u forgot to write in denominator?
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OpenStudy (anonymous):
what step?
OpenStudy (anonymous):
for f'(x) = 3x^2 - 1?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
ohh
OpenStudy (anonymous):
so 3x^2 -1/2x?
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OpenStudy (mertsj):
\[f(x)=\frac{3}{2}x-\frac{3}{2}+\frac{1}{2}x ^{-1}\]
OpenStudy (anonymous):
it will be 3x^2-1/2x^2
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
so what do i do after that?
OpenStudy (anonymous):
it is ur answer
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OpenStudy (mertsj):
\[f'(x)=\frac{3}{3}-\frac{1}{2}x ^{-2}\]
OpenStudy (anonymous):
so thats my derivative?
OpenStudy (mertsj):
Whoops. Typo. Should be 3/2 not 3/3
OpenStudy (anonymous):
yeah thats your derivative
OpenStudy (anonymous):
okay ii guess not putting 2x^2 is why i got it wrong
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
thx
OpenStudy (mertsj):
You were supposed to put 2x UNDER each term
OpenStudy (anonymous):
yea i did
OpenStudy (anonymous):
@Mertsj so i did it wrong?
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OpenStudy (anonymous):
@zepdrix can u help please? did i do it right or wrong?
zepdrix (zepdrix):
|dw:1362685192013:dw|Do you understand this step? ~Splitting up the fractions.
I wrote those ugly blobs to help show how we'll split it up.