Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

−6 + 12 − 24 + 48 − 96 + ... Is this a geometric series? If it is a geometric series, what's the next term? If it is a geometric series, give the ratio between successive terms

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

-2

OpenStudy (anonymous):

next term is192

OpenStudy (anonymous):

can you explain the formula?

OpenStudy (anonymous):

yeah second term / first term gives ratio

OpenStudy (anonymous):

multiply ratio in last term you'll get next term

OpenStudy (zehanz):

YOu have to ask yourself: can I find a constant number to multiply each term with, so that it gives the next one? If there is such a number, the sequence is geometric

OpenStudy (anonymous):

so its -2

OpenStudy (anonymous):

so if its a constant number means that the sequence is geometric?

OpenStudy (zehanz):

Yes!

OpenStudy (zehanz):

Every time, multiply with the same number to get the next term. That is a geometric sequence.

OpenStudy (anonymous):

no not necessary

OpenStudy (anonymous):

there are different types of series like AP and Gp .........

OpenStudy (anonymous):

whats AP and Gp?

OpenStudy (anonymous):

here if you ask for gp then common ratio (which can be both variable or constant ) is multiplied or divided to get the series

OpenStudy (anonymous):

AP is Arithmetic Progression and GP is geometric progression

OpenStudy (anonymous):

here you are dealing with gp

OpenStudy (anonymous):

like e.g. A.P.- 2,4,6,8............ G.P.- 3,6,9,.........

OpenStudy (anonymous):

for example if i have y^2 + y^3 + y^4 + y^5 + ... Is this a geometric series?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

here y is multiplied in each term to get next term

OpenStudy (anonymous):

thank you for your help

OpenStudy (anonymous):

mention not

OpenStudy (anonymous):

what about this series: 6+6(0.1)+6(0.1)^2+...6(0.1)^25

OpenStudy (anonymous):

How many terms are being added?

OpenStudy (anonymous):

here you have formula for gp series

OpenStudy (zehanz):

Same as counting from 0..25

OpenStudy (zehanz):

So that would be 26 terms...

OpenStudy (anonymous):

t= a(1-r^n/1-r) where r is common ratio and n is no. of term you can put t as last term given and calculate for n . this formula works only when r<1

OpenStudy (anonymous):

if r>1 then exchange r and 1

OpenStudy (anonymous):

wait why is it 26 terms?

OpenStudy (anonymous):

hey I gave you formula try that youll know

OpenStudy (anonymous):

what's "a" in the formula?

OpenStudy (anonymous):

how did you get the formula?

OpenStudy (anonymous):

i'm sorry for asking so many questions :(

OpenStudy (anonymous):

a is first term

OpenStudy (anonymous):

nevermind for question i am happy you are asking

OpenStudy (anonymous):

try it and do tell me if you get problem

OpenStudy (anonymous):

alright thanks

OpenStudy (anonymous):

mention not

OpenStudy (anonymous):

so for "n" in this series is 26?

OpenStudy (anonymous):

i dont know didn calculate if thats what u r getting then yes

OpenStudy (anonymous):

the "n" in the formula is the number of term you so the number if terms in this serie is 26?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

is the common ratio 0.1?

OpenStudy (anonymous):

it is right?

OpenStudy (anonymous):

Ill have to calculate but i am really sorry i cant cuz its nighttime here nad no lights and paper to work on

OpenStudy (anonymous):

don't worry about it

OpenStudy (anonymous):

can you help me with another series?

OpenStudy (anonymous):

yeah feel free

OpenStudy (anonymous):

Hey If you ever need help in mathematics or any science subject just drop me mail on chauhanbhimesh23@gmail.com and do leave reference.......i'm a bit forgetful person

OpenStudy (anonymous):

Ill contact you ASAP

OpenStudy (anonymous):

the series is 3-1+(1/3)-(1/9)+(1/27)-(1/81)+...

OpenStudy (anonymous):

I know the ratio is -1/3

OpenStudy (anonymous):

but what formula do I use to find the exact sum?

OpenStudy (anonymous):

the formula for sum is s= a (1-r^n/1-r)

OpenStudy (anonymous):

but this is a infinite geometric series. what do i put for "n"?

OpenStudy (anonymous):

ohk then use this s= a/1-r

OpenStudy (anonymous):

youll get the answer

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

my pleasure

OpenStudy (anonymous):

where you from?

OpenStudy (anonymous):

india

OpenStudy (anonymous):

how old are you?

OpenStudy (anonymous):

17

OpenStudy (anonymous):

applied to MIT this year just waiting for results

OpenStudy (anonymous):

hopefully you get in

OpenStudy (anonymous):

maybe maybe not

OpenStudy (anonymous):

I'm Mexico I applied to Yale but I didn't get in

OpenStudy (anonymous):

:(

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!