−6 + 12 − 24 + 48 − 96 + ...
Is this a geometric series?
If it is a geometric series, what's the next term?
If it is a geometric series, give the ratio between successive terms
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
-2
OpenStudy (anonymous):
next term is192
OpenStudy (anonymous):
can you explain the formula?
OpenStudy (anonymous):
yeah second term / first term gives ratio
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OpenStudy (anonymous):
multiply ratio in last term you'll get next term
OpenStudy (zehanz):
YOu have to ask yourself: can I find a constant number to multiply each term with, so that it gives the next one?
If there is such a number, the sequence is geometric
OpenStudy (anonymous):
so its -2
OpenStudy (anonymous):
so if its a constant number means that the sequence is geometric?
OpenStudy (zehanz):
Yes!
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OpenStudy (zehanz):
Every time, multiply with the same number to get the next term. That is a geometric sequence.
OpenStudy (anonymous):
no not necessary
OpenStudy (anonymous):
there are different types of series like AP and Gp .........
OpenStudy (anonymous):
whats AP and Gp?
OpenStudy (anonymous):
here if you ask for gp then common ratio (which can be both variable or constant ) is multiplied or divided to get the series
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OpenStudy (anonymous):
AP is Arithmetic Progression and GP is geometric progression
OpenStudy (anonymous):
here you are dealing with gp
OpenStudy (anonymous):
like e.g. A.P.- 2,4,6,8............
G.P.- 3,6,9,.........
OpenStudy (anonymous):
for example if i have
y^2 + y^3 + y^4 + y^5 + ...
Is this a geometric series?
OpenStudy (anonymous):
yeah
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OpenStudy (anonymous):
here y is multiplied in each term to get next term
OpenStudy (anonymous):
thank you for your help
OpenStudy (anonymous):
mention not
OpenStudy (anonymous):
what about this series:
6+6(0.1)+6(0.1)^2+...6(0.1)^25
OpenStudy (anonymous):
How many terms are being added?
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OpenStudy (anonymous):
here you have formula for gp series
OpenStudy (zehanz):
Same as counting from 0..25
OpenStudy (zehanz):
So that would be 26 terms...
OpenStudy (anonymous):
t= a(1-r^n/1-r) where r is common ratio and n is no. of term you can put t as last term given and calculate for n . this formula works only when r<1
OpenStudy (anonymous):
if r>1 then exchange r and 1
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OpenStudy (anonymous):
wait why is it 26 terms?
OpenStudy (anonymous):
hey I gave you formula try that youll know
OpenStudy (anonymous):
what's "a" in the formula?
OpenStudy (anonymous):
how did you get the formula?
OpenStudy (anonymous):
i'm sorry for asking so many questions :(
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OpenStudy (anonymous):
a is first term
OpenStudy (anonymous):
nevermind for question i am happy you are asking
OpenStudy (anonymous):
try it and do tell me if you get problem
OpenStudy (anonymous):
alright thanks
OpenStudy (anonymous):
mention not
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OpenStudy (anonymous):
so for "n" in this series is 26?
OpenStudy (anonymous):
i dont know didn calculate if thats what u r getting then yes
OpenStudy (anonymous):
the "n" in the formula is the number of term you so the number if terms in this serie is 26?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
is the common ratio 0.1?
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OpenStudy (anonymous):
it is right?
OpenStudy (anonymous):
Ill have to calculate but i am really sorry i cant cuz its nighttime here nad no lights and paper to work on
OpenStudy (anonymous):
don't worry about it
OpenStudy (anonymous):
can you help me with another series?
OpenStudy (anonymous):
yeah feel free
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OpenStudy (anonymous):
Hey If you ever need help in mathematics or any science subject just drop me mail on chauhanbhimesh23@gmail.com and do leave reference.......i'm a bit forgetful person
OpenStudy (anonymous):
Ill contact you ASAP
OpenStudy (anonymous):
the series is
3-1+(1/3)-(1/9)+(1/27)-(1/81)+...
OpenStudy (anonymous):
I know the ratio is -1/3
OpenStudy (anonymous):
but what formula do I use to find the exact sum?
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OpenStudy (anonymous):
the formula for sum is s= a (1-r^n/1-r)
OpenStudy (anonymous):
but this is a infinite geometric series. what do i put for "n"?
OpenStudy (anonymous):
ohk then use this s= a/1-r
OpenStudy (anonymous):
youll get the answer
OpenStudy (anonymous):
thanks
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OpenStudy (anonymous):
my pleasure
OpenStudy (anonymous):
where you from?
OpenStudy (anonymous):
india
OpenStudy (anonymous):
how old are you?
OpenStudy (anonymous):
17
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