Question

Need help with solving a radical inequality...

Answer 1

\[\sqrt{a-5} \le 4\]

Answer 2

square to get
\[a-5\leq 16\] and so \(a\leq 21\) but you have to be careful, there is another step

Answer 3

you cannot take the square root of a negative number, so you also have to solve
\[a-5\geq 0\] which means \(a\geq 5\)

Answer 4

final answer is therefore
\[5\leq a\leq 21\]

Answer 5

Thank you! :)