OpenStudy (anonymous):

Need help with solving a radical inequality...

4 years ago
OpenStudy (anonymous):

$\sqrt{a-5} \le 4$

4 years ago
OpenStudy (anonymous):

square to get $a-5\leq 16$ and so $$a\leq 21$$ but you have to be careful, there is another step

4 years ago
OpenStudy (anonymous):

you cannot take the square root of a negative number, so you also have to solve $a-5\geq 0$ which means $$a\geq 5$$

4 years ago
OpenStudy (anonymous):

final answer is therefore $5\leq a\leq 21$

4 years ago
OpenStudy (anonymous):

Thank you! :)

4 years ago