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Verify the identity. - tan^2(x) + sec^2(x) = 1
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sin^(x)+cos^2(x)=1 ] divide both sides by cos^(x) you will get the required answer...
if it is not clear let me know to prove it for u in details...
tan^2x= sec^2x-1
\[-(\sec ^2x-1)+\sec ^2x=1\]
\[-\sec ^2x+1+\sec ^2x=1\]
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\[-\sec ^2x+\sec ^2x+1=1\]
\[0+1=1\]
\[1=1\]
@Mertsj are u sure that's how?
There are multiple ways. That is one of them. You could also do what mathsmind said or you could replace sec^2x with 1+tan^2x
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yes both ways are correct...
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