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OpenStudy (anonymous):
\[\sum_{k=3}^{\infty} (1/2)^k\]
OpenStudy (anonymous):
Find the partial sum and take it's limit
OpenStudy (anonymous):
I think the answer is 1/4 since it's infinite geometric series
OpenStudy (anonymous):
how do you find the partial sum?
OpenStudy (anonymous):
ahh don't think that is required here unless you're taking a course in analysis
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OpenStudy (anonymous):
so how do you know that is 1/4
OpenStudy (anonymous):
Google infinite geometric series; there's a formula for that
terenzreignz (terenzreignz):
Here... you know that geometric series take this form, right?
\[\huge S=a + ar + ar^2+ar^3+...\]
right?
Where a is the first term and r is the common ratio.
OpenStudy (anonymous):
yes
terenzreignz (terenzreignz):
Well, let's rearrange.
\[\huge S-a=ar+ar^2+ar^3+ar^4+...\]following me so far? :)
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OpenStudy (anonymous):
yes
terenzreignz (terenzreignz):
Okay, let's divide both sides by r, the common ratio, we get...
\[\huge \frac{S-a}{r}=a+ar+ar^2+ar^3+...\]Catch me so far?
OpenStudy (anonymous):
yes
terenzreignz (terenzreignz):
Now, you'll notice that the right-side of this equation is nothing but S again. Right?
OpenStudy (anonymous):
yes
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terenzreignz (terenzreignz):
So, we now have
\[\huge \frac{S-a}{r}=S\]Now we just have to solve for S.