A street light is at the top of a 17 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 8 ft/sec along a straight path. How fast is the tip of her shadow moving when she is 50 ft from the base of the pole? plz help
I haven't seen a problem like that and it is going to take me more time than I have to figure out. If I were you, I would look that one up on google. Type the problem word for word in the search and see if you can find either that problem or a similar one.
If it was a right angle question I could've helped you out.
no its a derivative based question but thanks anyways
no problem
it will be approx. 12.36 ft/sec.|dw:1362703526063:dw|
in the fig let BD is y so the dy/dt=8 ft/s. let BE=x and we have to find out dx/ dt when x=50. Now triangle ABE and CDE are similar so 17/6= x/x-y which gives you the result 11x=17y. Differentiate both sides with respect to t it is 11 dx/dt= 17 dy/dt now put the value.
i still confused
Dr. J already gave you the answer. It's 12.36 ft/sec.
Refer to the attached solution solved with Mathematica.
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