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use basic identities to simplify: cosx-cosxsin^2x and cotxsecxsinx
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cosx-cosxsin²x Factor cosx out. cosx(1-sin²x) = cosx(cos²x) = cos³x
cotxsecxsinx Knowing that \(\cot x = \dfrac{\cos x}{\sin x}\) and \(\sec x = \dfrac{1}{\cos x }\) cotxsecxsinx = 1
thank you! what about proving this identity: (cscx-1)/(cscx+1) = (cot^2x)/(csc^2x+2cscx+1)
Factor csc²x+2cscx+1 Then multiply both sides by (cscx + 1)²
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