Question

calc II separable equation, please help :)

Answer 1

\[\frac{ du }{ dt }=e ^{6u+8t}\] given that u(0)=8. So this is how I set it up \[\int\limits_{}^{}e ^{-6u}du=\int\limits_{}^{}e ^{8t}dt\]

Answer 2

Is that right so far?

Answer 3

yes looks right. so far.

Answer 4

Okay, so this is what I got for my integration: \[\frac{ -e ^{-6u} }{ 6 }=\frac{ e ^{8t} }{ 8 }+c\]

Answer 5

and then using that u(0)=8, I found that c=-0.125.

Answer 6

I actually have already worked through this problem, but I got the wrong answer at the end so I'm trying to figure out where I'm going wrong

Answer 7

so then I end up with \[\frac{ -e ^{-6u} }{ 6 }=\frac{ e ^{8t} }{ 8 }-0.125\]

Answer 8

so then my final answer was u(t)=\[\frac{ 1 }{ 6 }\ln(\frac{ 3 }{ 4 }e ^{8t}-\frac{ 3 }{ 4 })\]

Answer 9

but the book says that isn't the right answer

Answer 10

hmm well i also got c same as u.. well what answer book says?

Answer 11

well, it's actually webwork, so it just tells me that my answer is wrong, I'm not sure what the right answer is

Answer 12

I'm thinking something must be wrong with the way I'm doing the algebra to rearrange it in terms of u(t)?

Answer 13

well i am not sure but the way u solved question looks fine and the answer should be the one u got..

Answer 14

hmmm. Okay. I'll ask the tutor at 8. Thanks anyway :)