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Calculus1
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OpenStudy (anonymous):
1) F(x)=4^xlog(small=>)7(x)]
2) f(x)=[Inx]^4
3)f(x)=2x^(4x)
4)f(x)=In(sqrt(6x+7)(7x-3))
13 years ago
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OpenStudy (anonymous):
@wio
13 years ago
OpenStudy (anonymous):
Okay, what's difficult?
13 years ago
OpenStudy (anonymous):
Logarithmic Derivatives!
13 years ago
OpenStudy (anonymous):
\[
(\ln(F(x)))' = \frac{F'(x)}{F(x)}
\]
13 years ago
OpenStudy (anonymous):
You want to take the logarithm of both sides, simplify things, and then implicitly differentiate.
13 years ago
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OpenStudy (anonymous):
how do i do that? :O
13 years ago
OpenStudy (anonymous):
Is this correct?\[
F(x)=4^x\log_7(x)
\]
13 years ago
OpenStudy (anonymous):
yes, thars right!
13 years ago
OpenStudy (anonymous):
There is no need to do this one with logarithmic differentiation, it'd be easier to do product rule.
13 years ago
OpenStudy (anonymous):
yea i was told by someone that but my teacher want me to do it by using Logarithmic Derivatives rules
13 years ago
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OpenStudy (anonymous):
could you teach me please?
13 years ago
OpenStudy (anonymous):
\[
\ln[F(x)]=\ln[4^x\log_7(x)] = x\ln(4)+\ln[\log_7(x)]
\]Differentiate both sides: \[
\frac{F'(x)}{F(x)} = \ln(4) + \frac{\frac{1}{x\ln(7)}}{\log_7(x)}
\]
13 years ago
OpenStudy (anonymous):
Put back in the value for \(F(x)\)\[
\frac{F'(x)}{4^x\log_7(x)} = \ln(4) + \frac{\frac{1}{x\ln(7)}}{\log_7(x)}
\]Simplify a bit: \[
F'(x) = 4^x\log_7(x)\ln(4) + \frac{4^x}{x\ln(7)}
\]
13 years ago
OpenStudy (anonymous):
thats really cool how you solve the problem easily. the last sentence is the answer ?
13 years ago
OpenStudy (anonymous):
I showed every step...
13 years ago
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OpenStudy (anonymous):
thank you. !
13 years ago
OpenStudy (anonymous):
how do the next question?
13 years ago
OpenStudy (anonymous):
One question per help.
13 years ago
OpenStudy (anonymous):
you wont help me?
13 years ago
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