Find the equation of the tangent line to the curve y= (x^2-3)^8 at the point (2,1) using derivatives..

Question

zepdrix · Answer

Buhaha c: Look at that cute lil dawg! c:

zepdrix · Answer

We're looking to form a line which we can either write in slope-intercept form $\large y=mx+b$ or in point-slope form $\large y-y_o=m(x-x_o)$.

It might make more sense to write it in point-slope form, since we've been given a set of points that we can call $\large (x_o,y_o)=(2,1)$

Our slope $\large m$ is given by $\large m=f'(2)$
So we want to first find the derivative of our function $\large f$, then plug 2 into it! That will be our $\large m$.

zepdrix · Answer

Do you need any help finding the derivative of $\large f(x)$?

anonymous · Answer

Ohh, makes so much sense now. I know how to derive it, just not the tangent line and how to find that part, that's all. Thanks!

zepdrix · Answer

Oh ok cool c: