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Mathematics 19 Online
OpenStudy (anonymous):

Ok so i have a triangle (not right triangle) that has sides that are 12 15 and 16 feet long. That's all i know. How do i find the area?

OpenStudy (johnweldon1993):

Area of a triangle is 1/2base * height

OpenStudy (anonymous):

yeah but there is no height.

OpenStudy (anonymous):

oh 16 is the base. 12 is the left sinde and 15 is the right side

OpenStudy (johnweldon1993):

|dw:1362710949873:dw| see how the line for height seperates the big triangle into 2 right triangles?

OpenStudy (johnweldon1993):

So now you have 2 triangles...1 with hypotenuse 15 ...a base of x...and height of h another with hypotenuse 12...base 16-x ..and height h

OpenStudy (anonymous):

Ok so now I just find the area of the smaller ones?

OpenStudy (johnweldon1993):

in general yes....so you take the pythagorean theorem for each triangle...lets focus on the smaller one first

OpenStudy (raden):

use the Heron's formula area = sqrt{s(s-a)(s-b)(s-c)} with a,b,c are sides of triangle, s is half of the perimeter of triangle

OpenStudy (johnweldon1993):

H² + B² = 12² We want height so H² = 144 - B² Now we look at the other triangle 15² = H² + (16-x) and sub in what you got for H²

OpenStudy (johnweldon1993):

Actually yeah...instead of step by step...use the Heron's formula

OpenStudy (johnweldon1993):

Like RadEn said

OpenStudy (anonymous):

Ok. Thank you so much! Both of you! @johnweldon1993 @RadEn

OpenStudy (anonymous):

I wish I could give you both best response :P

OpenStudy (johnweldon1993):

Ehh I would give it to RadEn, he made it a LOT simpler...in math...we like simpler lol

OpenStudy (anonymous):

ok. Thanks maybe you will get one later! @johnweldon1993

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