Ok so i have a triangle (not right triangle) that has sides that are 12 15 and 16 feet long. That's all i know. How do i find the area?
Area of a triangle is 1/2base * height
yeah but there is no height.
oh 16 is the base. 12 is the left sinde and 15 is the right side
|dw:1362710949873:dw| see how the line for height seperates the big triangle into 2 right triangles?
So now you have 2 triangles...1 with hypotenuse 15 ...a base of x...and height of h another with hypotenuse 12...base 16-x ..and height h
Ok so now I just find the area of the smaller ones?
in general yes....so you take the pythagorean theorem for each triangle...lets focus on the smaller one first
use the Heron's formula area = sqrt{s(s-a)(s-b)(s-c)} with a,b,c are sides of triangle, s is half of the perimeter of triangle
H² + B² = 12² We want height so H² = 144 - B² Now we look at the other triangle 15² = H² + (16-x) and sub in what you got for H²
Actually yeah...instead of step by step...use the Heron's formula
Like RadEn said
Ok. Thank you so much! Both of you! @johnweldon1993 @RadEn
I wish I could give you both best response :P
Ehh I would give it to RadEn, he made it a LOT simpler...in math...we like simpler lol
ok. Thanks maybe you will get one later! @johnweldon1993
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