24,673.32=12,000(1+(.08/4))^(4*t)
can someone help me solve for t (time)?

Question

24,673.32=12,000(1+(.08/4))^(4*t)
can someone help me solve for t (time)?

anonymous · Answer

@NotTim @ghass1978 @campbell_st @ash2326 @AccessDenied

campbell_st · Answer

if the equation is

$$24 673.32 = 12000(1 + (\frac{0.8}{4}))^{4t}$$

ok... so divide both sides of the equation by 12000

or 

$$2.05611 = (1 + (0.08/4))^{4t}$$

next take the log of both sides. Base e is fine$$\ln(2.05611) = 4t \times \ln(1 + (\frac{0.08}{4})$$

this should make it easier to find t

campbell_st · Answer

you will need to know a few log laws to simplify it

anonymous · Answer

anyone in 11th at c academy

hero · Answer

^ no

hero · Answer

@mariomintchev, I already explained to you how to do it.

anonymous · Answer

ok im getting a weird answer

anonymous · Answer

i got like -4.6

campbell_st · Answer

well I got a sensible answer... its positive... which is important as I think t stands for time...

hero · Answer

You already know -4.6 definitely isn't it

campbell_st · Answer

try doing some simplification... 1 + 0.08/4 = 1.02

$$\frac{\ln(2.05611)}{\ln(1.02)} = 4t$$

anonymous · Answer

9.1

campbell_st · Answer

well its positive ... like time... so go and substitute it into the original equation and see if you get

24673.32.... best way of checking

anonymous · Answer

its correct :)

campbell_st · Answer

well then its a good solution.