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Mathematics 15 Online
OpenStudy (anonymous):

2/(x-6)^3 what are the vertical and horizontal asymptotes of this equation

OpenStudy (campbell_st):

the denominator can't be zero so the value that makes it zero will be the vertical asymptote. the horizontal is found by dividing the numeration by the denominator.. how many times does (x-6)^3 divide into 2.... answer is 0 so the hotizontal asymptote is y = 0 hope this helps.

OpenStudy (anonymous):

and theres no vertical asymptote correct?

OpenStudy (campbell_st):

there is a vertical asymptote... what value makes x - 6 = 0 thats the asymptote

OpenStudy (anonymous):

xo vertical =6 and horizontal =none

OpenStudy (campbell_st):

thats correct

Directrix (directrix):

@emilyyy --> I think there is a horizontal asymptote, y = 0, for the graph of y = 2/(x-6)^3. Consider the end behavior of the function.

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