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2/(x-6)^3 what are the vertical and horizontal asymptotes of this equation
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the denominator can't be zero so the value that makes it zero will be the vertical asymptote. the horizontal is found by dividing the numeration by the denominator.. how many times does (x-6)^3 divide into 2.... answer is 0 so the hotizontal asymptote is y = 0 hope this helps.
and theres no vertical asymptote correct?
there is a vertical asymptote... what value makes x - 6 = 0 thats the asymptote
xo vertical =6 and horizontal =none
thats correct
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@emilyyy --> I think there is a horizontal asymptote, y = 0, for the graph of y = 2/(x-6)^3. Consider the end behavior of the function.
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