Hi! Good Afternoon. Can someone help me about the area of polar coordinates? I saw in a certain example that the interval Of the equation r=2-sinΘ and r=3sinΘ is Π/6≤Ɵ≤Π/2. Can someone explain how it becomes?
hey welcome to openstudy !!
Can you answer my question. Thank you
The inverval of the equation? Hmm I'm not quite sure what that means. Here is a nice pretty graph of the two functions. https://www.desmos.com/calculator/xlhjges48e It seems they intersect at \(\large \theta=\pi/6\) and again at \(\large \theta=5\pi/6\).
yes. it intersects at θ=π/6 and again at θ=5π/6, but the interval that i posted is also right? is it? then i will just multiply it by 1/2? am i right?
What are you trying to do exactly? Find the area of the intersecting regions? If so, then yes you could do that. Setup your interval from \(\large \pi/6\) to \(\large \pi/2\) and just multiply the by \(\large 2\) since the area is symmetric up there.
yes, that was exactly what i mean.. but, is there any formula to find the intersecting regions?
For finding points of intersection? \[\large r=2-\sin \theta \qquad \qquad r=3\sin \theta\] Set your two equations equal to one another,\[\large 2-\sin \theta=3\sin \theta\] And then solve for \(\large \theta\). We will do so by first solving for \(\large \sin\theta\) and from there remembering our special angles. Add sin theta to both sides,\[\large 2=4\sin \theta\]Divide by 4,\[\large \frac{1}{2}=\sin\theta\] Can you recall what special angle produces 1/2 from the sine function? :D
Those are special angles on the unit circle c: \(\large \sin \dfrac{\pi}{6}=\dfrac{1}{2}\) \(\large \sin \dfrac{5\pi}{6}=\dfrac{1}{2}\) You should definitely have the unit circle memorized if you're doing this for a school class c: Yah you might be able to get the angle by arcsine, if you have a good calculator it might even give it to you as a nice fraction instead of a messy decimal.
okay i think i remember those special angles. but i did not memorize it.. by the way, can you give me an example that i can practice to solve at home afterwards? if its okay. :D
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