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Physics 13 Online
OpenStudy (yrelhan4):

magnetism question @Mashy

OpenStudy (anonymous):

C is the answer!

OpenStudy (anonymous):

:D

OpenStudy (yrelhan4):

okay!

OpenStudy (anonymous):

42??

OpenStudy (yrelhan4):

both.

OpenStudy (anonymous):

this is quite simple :O.. just use Biot Savart's law :O

OpenStudy (yrelhan4):

ok what i did is. dI=J.dA where dA=2*pie*r dr. integrated and found B through amperes law. but then i noticed there is no 'a' in the answer.

OpenStudy (yrelhan4):

how will i use it here? idl*r/r^2 *mu/4pi ?

OpenStudy (yrelhan4):

r^3 *

OpenStudy (anonymous):

You have a direct formula for current due to a long straight conductor derived from ampere's circuital law.. \[B = \frac{ \mu0 }{ 4 \pi }\frac{ I }{ r }\] all you need to know now is I.. for that we gotta use current density!

OpenStudy (yrelhan4):

2I/r??

OpenStudy (anonymous):

no no wait wait wait!!

OpenStudy (yrelhan4):

also when i find I, 'a' will be there in the answer. but no option has a.

OpenStudy (anonymous):

wait. lemme first get the answer.. and verify ok?

OpenStudy (yrelhan4):

alright. should i tell you the answer? :P

OpenStudy (anonymous):

no no wait..

OpenStudy (anonymous):

b ?

OpenStudy (yrelhan4):

CANT YOU GIVE MY EXAM? :o

OpenStudy (anonymous):

:D.. ok lemme draw1

OpenStudy (anonymous):

|dw:1362733443592:dw| does that make sense?

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