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OpenStudy (anonymous):
C is the answer!
OpenStudy (anonymous):
:D
OpenStudy (yrelhan4):
okay!
OpenStudy (anonymous):
42??
OpenStudy (yrelhan4):
both.
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OpenStudy (anonymous):
this is quite simple :O.. just use Biot Savart's law :O
OpenStudy (yrelhan4):
ok what i did is.
dI=J.dA where dA=2*pie*r dr. integrated and found B through amperes law.
but then i noticed there is no 'a' in the answer.
OpenStudy (yrelhan4):
how will i use it here? idl*r/r^2 *mu/4pi ?
OpenStudy (yrelhan4):
r^3 *
OpenStudy (anonymous):
You have a direct formula for current due to a long straight conductor derived from ampere's circuital law..
\[B = \frac{ \mu0 }{ 4 \pi }\frac{ I }{ r }\]
all you need to know now is I.. for that we gotta use current density!
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OpenStudy (yrelhan4):
2I/r??
OpenStudy (anonymous):
no no wait wait wait!!
OpenStudy (yrelhan4):
also when i find I, 'a' will be there in the answer. but no option has a.
OpenStudy (anonymous):
wait. lemme first get the answer.. and verify ok?
OpenStudy (yrelhan4):
alright. should i tell you the answer? :P
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