if y=square root(xsinx), derivative of this would be...?
\((\sqrt{x .\sin x})'=...\) typical chain rule+product rule problem, whats the derivative of \(\sqrt x \) ?
1/2(x)^-1/2
yes, so ,applying chain rule, \((\sqrt{x .\sin x})'=...\)
op, got answeer ok what about the 100th derivative of sin3x???
good! whats 1st derivative ?
I think the answer is \[\sqrt{x}/2.cosx + \sqrt{sinx}/2\sqrt{x}\]
shrini, the answer is (xcosx+sinx)/2(xsinx)^-1/2 and the 1st derivative is sin3x is cos3x?
*ofsin3x
just cos 3x ?? or 3cos 3x ?
@lucy4104 I used the product rule and I got this. I don't know if I'm right.
(sin 3x)' = cos 3x *(3x)' = 3* cos 3x using chain rule, whats the 2nd derivative ?
did you use the chain rule, @hartnn ? and I used the chain rule, shrini
yes.
@lucy4104 \[\sqrt{xsinx}=\sqrt{x}*\sqrt{sinx}\] So, i used the product rule.
ok, I get how you got first derivative, so would the second be 9cos3x?
d/dx cos x = - sin x so, d/dx (3 cos 3x) = 3 (-sin 3x) (d/dx 3x) = -9 sin 3x ok ?
ok
and third derivative.... ? the point is that we will find first few derivatives, then generalize it in terms of n'th derivative and then put n=100
ok
third deriv -9sin3x----->-9cos3x*3----->-27cos3x
now lets generalize : 1st derivative : 3^1 cos 3x 2nd derivative : -3^2 sin 3x 3rd derivative : -3^3 cos 3x 4th derivative : +3^4 sin 3x and so on.
so, for 'odd' derivative , we see cos 3x term, and for 'even' derivative, we see 'sin 3x'
and for n'th derivative, we see 3^n term, clear so far ?
what about the negative?
yes, after every 2 positive derivatives, comes 2 negative derivative... or, can i say, 4th, 8th, 12th,.... 100th, 104th..... derivative will be positive, that is derivative which are multiples of 4 are positive... ?
that last part confuzzled me
try and figure out by yourself, whether 100th derivative will be positive or negative?
1st was pos, 2and 3 was neg, 4th and 5th was pos, 6and 7 was neg, 8 and 9 is pos, 10 and 11 is neg, 12 and 13 is pos, 14, 15 is neg, 16 and 17 is pos. oh I see 4, 8, 12, 16 are positive and then the one number after it is also positive.
good observation, what about 100th ?
with positive derivative and since 100 is even, we'll have sin 3x and term 3^100. 100th derivative of sin 3x will be 3^100 sin 3x
oh!!! ok thanx
welcome ^_^
Join our real-time social learning platform and learn together with your friends!