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Mathematics 13 Online
OpenStudy (anonymous):

if y=square root(xsinx), derivative of this would be...?

hartnn (hartnn):

\((\sqrt{x .\sin x})'=...\) typical chain rule+product rule problem, whats the derivative of \(\sqrt x \) ?

OpenStudy (anonymous):

1/2(x)^-1/2

hartnn (hartnn):

yes, so ,applying chain rule, \((\sqrt{x .\sin x})'=...\)

OpenStudy (anonymous):

op, got answeer ok what about the 100th derivative of sin3x???

hartnn (hartnn):

good! whats 1st derivative ?

OpenStudy (anonymous):

I think the answer is \[\sqrt{x}/2.cosx + \sqrt{sinx}/2\sqrt{x}\]

OpenStudy (anonymous):

shrini, the answer is (xcosx+sinx)/2(xsinx)^-1/2 and the 1st derivative is sin3x is cos3x?

OpenStudy (anonymous):

*ofsin3x

hartnn (hartnn):

just cos 3x ?? or 3cos 3x ?

OpenStudy (anonymous):

@lucy4104 I used the product rule and I got this. I don't know if I'm right.

hartnn (hartnn):

(sin 3x)' = cos 3x *(3x)' = 3* cos 3x using chain rule, whats the 2nd derivative ?

OpenStudy (anonymous):

did you use the chain rule, @hartnn ? and I used the chain rule, shrini

hartnn (hartnn):

yes.

OpenStudy (anonymous):

@lucy4104 \[\sqrt{xsinx}=\sqrt{x}*\sqrt{sinx}\] So, i used the product rule.

OpenStudy (anonymous):

ok, I get how you got first derivative, so would the second be 9cos3x?

hartnn (hartnn):

d/dx cos x = - sin x so, d/dx (3 cos 3x) = 3 (-sin 3x) (d/dx 3x) = -9 sin 3x ok ?

OpenStudy (anonymous):

ok

hartnn (hartnn):

and third derivative.... ? the point is that we will find first few derivatives, then generalize it in terms of n'th derivative and then put n=100

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

third deriv -9sin3x----->-9cos3x*3----->-27cos3x

hartnn (hartnn):

now lets generalize : 1st derivative : 3^1 cos 3x 2nd derivative : -3^2 sin 3x 3rd derivative : -3^3 cos 3x 4th derivative : +3^4 sin 3x and so on.

hartnn (hartnn):

so, for 'odd' derivative , we see cos 3x term, and for 'even' derivative, we see 'sin 3x'

hartnn (hartnn):

and for n'th derivative, we see 3^n term, clear so far ?

OpenStudy (anonymous):

what about the negative?

hartnn (hartnn):

yes, after every 2 positive derivatives, comes 2 negative derivative... or, can i say, 4th, 8th, 12th,.... 100th, 104th..... derivative will be positive, that is derivative which are multiples of 4 are positive... ?

OpenStudy (anonymous):

that last part confuzzled me

hartnn (hartnn):

try and figure out by yourself, whether 100th derivative will be positive or negative?

OpenStudy (anonymous):

1st was pos, 2and 3 was neg, 4th and 5th was pos, 6and 7 was neg, 8 and 9 is pos, 10 and 11 is neg, 12 and 13 is pos, 14, 15 is neg, 16 and 17 is pos. oh I see 4, 8, 12, 16 are positive and then the one number after it is also positive.

hartnn (hartnn):

good observation, what about 100th ?

hartnn (hartnn):

with positive derivative and since 100 is even, we'll have sin 3x and term 3^100. 100th derivative of sin 3x will be 3^100 sin 3x

OpenStudy (anonymous):

oh!!! ok thanx

hartnn (hartnn):

welcome ^_^

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